What is the angular momentum of a rod with a mass of #8 kg# and length of #6 m# that is spinning around its center at # 2 Hz#?

1 Answer
Aug 13, 2016

Answer:

#"The angular momentum of rod is " 96pi#

Explanation:

#"The angular momentum of a rod spinning its center can be calculated using " L=I*omega#

#L:"represents angular momentum"#
#I:"represents moment of inertia"#
#omega:"represents angular velocity "#

#omega=2*pi*f" where f is frequency"#

#omega=2*pi*2=4pi#

#I=1/12*m*l^2(" moment of inertia for a rod spinning around its center")#

#m=8" kg ";l=6" m"#

#I=1/12*8*6^2=(8*36)/12=8*3=24#

#I=24*4pi=96 pi#