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#(3+r)^2 =9+r#

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Answer 1 · 2018-03-02T19:49:50

#r = 0# and #r = -5#

Given: #(3+r)^2 =9+r#

Expand the square:

#r^2+6r+9 = 9+r#

Subtract #9+r# from both sides:

#r^2+5r = 0#

Factor:

#r(r+5)=0#

#r = 0# and #r = -5#

Answer 2 · 2018-03-02T19:50:53

#r=0,r=-5#

#(3+r)^2=9+r#

Expanding
#3^2+2xx3xxr+r^2=9+r#

#9+6r+r^2=9+r#
Simplifying
#6r+r^2-r=0#

#r^2+5r=0#
Factorising
#r(r+5)=0#

#r=0, #or #r+5=0#

#r=0,r=-5#