# What is the antiderivative of (5/x)^2?

I found: $- \frac{25}{x} + c$
$\int {\left(\frac{5}{x}\right)}^{2} \mathrm{dx} = \int 25 {x}^{-} 2 \mathrm{dx} =$ that can be integrated as a power giving:
$= 25 \frac{{x}^{-} 1}{-} 1 + c = - \frac{25}{x} + c$