Question

What is the antiderivative of `pi^(x-1)dx`?

Answer 1

The answer is: `pi^(x-1)/lnpi+c`.

Since:

`inta^f(x)*f'(x)dx=a^f(x)/lna+c`

Than:

`intpi^(x-1)dx=pi^(x-1)/lnpi+c`.