# What is the antiderivative of pi^(x-1)dx?

The answer is: ${\pi}^{x - 1} / \ln \pi + c$.
$\int {a}^{f} \left(x\right) \cdot f ' \left(x\right) \mathrm{dx} = {a}^{f} \frac{x}{\ln} a + c$
$\int {\pi}^{x - 1} \mathrm{dx} = {\pi}^{x - 1} / \ln \pi + c$.