What is the antiderivative of (t^2)/(t^2 + 1) dt from 1 to sq. rt. x?
I got (x^2)/[(2)(x^2 + 1)(sq. rt. x)]. Is this correct?
I got (x^2)/[(2)(x^2 + 1)(sq. rt. x)]. Is this correct?
1 Answer
Feb 2, 2018
Explanation:
Let,