# What is the antiderivative of x^2/5? thanks!?

$\textcolor{red}{{x}^{3} / 15 + c}$
$\int {x}^{2} / 5 \mathrm{dx} =$
Remember that the integral of ${x}^{n}$ is ${x}^{n + 1} / \left(n + 1\right)$ so:
$\int {x}^{2} / 5 \mathrm{dx} = \frac{1}{5} \int {x}^{2} \mathrm{dx} = \frac{1}{5} {x}^{2 + 1} / \left(2 + 1\right) + c = \frac{1}{5} {x}^{3} / 3 + c =$
$= {x}^{3} / 15 + c$