What is the approximate density of the mineral with a mass of #"262.2 g"# that displaces #"46 cm"^3# of water?
The idea here is that the volume of water displaced by the mineral will actually give you the volume of the mineral.
When you place the mineral in a graduated cylinder, for example, that contains a known volume of water, the level of the water will rise.
The difference between the level of the water with the mineral and the level of the water without the mineral is the volume of water displaced by the mineral, i.e. the volume of the mineral.
So, you know that you mineral has a mass of
#rho = "262.2 g"/"46 cm"^3 = color(darkgreen)(ul(color(black)("5.7 g cm"^(-3))))#
The answer is rounded to two sig figs, the number of sig figs you have for the volume of the water displaced by the mineral.