# What is the arclength of f(x)=sqrt(4-x^2)  in the interval [-2,2]?

Jul 10, 2018

The arc length is $2 \pi$ units.

#### Explanation:

This is a semi circle of radius $2$. We simply find the perimeter of the full circle of radius $2$ and divide it by $2$ to get our arc length.

$P = 2 \left(2\right) \pi = 4 \pi$

$\frac{P}{2} = \frac{4 \pi}{2} = 2 \pi$

Therefore the arc length is $2 \pi$ units.

Hopefully this helps!