What is the arclength of #(t-e^(2t),lnt)# on #t in [1,12]#?
The arclength is around
First, let's get a sense of how long the arclength might actually be. It will go from
We can tell that this distance will be very big, so that means the arclength is also very big.
To calculate the actual arclength, we'll need to get an integral in the form of
(This link does a great job of explaining arc lengths of parametric curves.)
First, split the parametric function into a function of
Now, differentiate each one and get
Now, plug these into the aforementioned integral with the appropriate bounds. You'll see that the
At this point, you should probably plug this integral into a calculator because the function probably doesn't have an antiderivative, and even if it does it would be a pain to calculate.
A calculator should spit out something around