What is the area under the polar curve #f(theta) = 3theta^2+thetasin(4theta-(5pi)/12 ) +cos(2theta-(pi)/3)# over #[pi/8,pi/6]#?
Area under the polar curve for any function
So all we have to do is plugin whole
That would give us,
Doing this integral by hand would be little tedious so you can just plug integral in your calculator and get the answer.
The answer would be 0.455