Question

What is the average force on the puck by the stick?

A 0.16 kg hockey puck is moving on an icy horizontal surface with a speed of 5 m/s. A player strikes the puck by a hockey stick, after the impact the puck moves in opposite direction with a speed of 9 m/s. If the puck was in contact with the stick for 0.005 s, what is the average force on the puck by the stick?

Answer 1

`F= -448 N`

Explanation:

The impulse formulas

`I= mDeltav`
`I= FDeltat`

So:
`mDeltav= FDeltat`

Solving for `F`:
`(mDeltav)/(Deltat)= F`

`Deltav= v_f-v_i`

`v_f= -9m/s`
`v_i= 5m/s`

`F= ((0.16 kg)(-9m/s-5m/s))/(0.005s)= -448 N`