Question

What is the average value of `20+10xe^(-x/3)` over the interval of 0< x <15?

Answer 1

Average rate of change in (0,15)=`10e^-5`

Explanation:

The given function is continuous in the closed interval [0,15]

Average rate of change in (0,15)= `(f(15)-f(0))/(15-0)`

= `((20+150e^-15)-20)/(15`

=`10e^-5`