What is the axis of symmetry and vertex for the graph #f(x) = -x^2 + 10#?

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Answer 1 · 2016-09-16T15:55:26

Vertex #(0,10)#

Axis of symetry #x=0#

Given -

#y=-x^2+10#

Let us rewrite it as -

#y=x^2+0x+10#

Vertex

X-Coordinate

#x=(-b)/(2a)=0/(2xx1)=0#

Y - Coordinate

#y=0^2+10#
#y=10#

Vertex #(0,10)#

Axis of symetry #x=0#