# What is the axis of symmetry and vertex for the graph f(x) = -x^2 + 10?

Sep 16, 2016

Vertex $\left(0 , 10\right)$

Axis of symetry $x = 0$

#### Explanation:

Given -

$y = - {x}^{2} + 10$

Let us rewrite it as -

$y = {x}^{2} + 0 x + 10$

Vertex

X-Coordinate

$x = \frac{- b}{2 a} = \frac{0}{2 \times 1} = 0$

Y - Coordinate

$y = {0}^{2} + 10$
$y = 10$

Vertex $\left(0 , 10\right)$

Axis of symetry $x = 0$