# What is the axis of symmetry and vertex for the graph y= -4x^2?

Jan 10, 2018

Axis of symmetry is $x = 0$ and vertex is $\left(0 , 0\right)$

#### Explanation:

When an equation $y = a {x}^{2} + b x + c$ is converted in form

$y = a {\left(x - h\right)}^{2} + k$

axis of symmetry is $x - h = 0$ and vertex is $\left(h , k\right)$

As we can write $y = - 4 {x}^{2}$

as $y = - 4 {\left(x - 0\right)}^{2} + 0$

axis of symmetry is $x - 0 = 0$ i.e. $x = 0$ i.e. $y$-axis and vertex is $\left(0 , 0\right)$

graph{-4x^2 [-5.146, 4.854, -3.54, 1.46]}