What is the axis of symmetry and vertex for the graph y=8(x-10)^2-16?

Aug 9, 2017

Vertex is at $\left(10 , - 16\right)$
Axis of symmetry is $x = 10$

Explanation:

$y = 8 {\left(x - 10\right)}^{2} - 16$ . Comparing with standard vertex form of

equation y=a(x-h)^2+k ; (h,k) being vertex , we find here

$h = 10 , k = - 16$ . So vertex is at $\left(10 , - 16\right)$

Axis of symmetry is $x = h \mathmr{and} x = 10$

graph{8(x-10)^2-16 [-40, 40, -20, 20]} [Ans]