What is the axis of symmetry and vertex for the graph #y = x^2 - 14x + 13 #?

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Answer 1 · 2016-02-23T12:21:41

Look at explanantion

Given:#" "y=x^2-14x+13#

Consider the -14 from #-14x#

Apply: #(-1/2)xx(-14)=+7#

From this we have

#x_("vertex")=+7#

So axis of symmetry is #x=7#

Substitute 7 for #x# in the original equation to find

#y_("vertex")=(7)^2-14(7)+13#

I will let you finish that bit!