# What is the axis of symmetry and vertex for the graph y = x^2 - 14x + 13 ?

Feb 23, 2016

Look at explanantion

#### Explanation:

Given:$\text{ } y = {x}^{2} - 14 x + 13$

Consider the -14 from $- 14 x$

Apply: $\left(- \frac{1}{2}\right) \times \left(- 14\right) = + 7$

From this we have

${x}_{\text{vertex}} = + 7$

So axis of symmetry is $x = 7$

Substitute 7 for $x$ in the original equation to find

${y}_{\text{vertex}} = {\left(7\right)}^{2} - 14 \left(7\right) + 13$

I will let you finish that bit!