# What is the axis of symmetry and vertex for the graph y = x^2 – 3x + 4?

Vertex is at $\left(\frac{3}{2} , \frac{7}{4}\right)$ and axis of symmetry is $x = \frac{3}{2}$
$y = {x}^{2} - 3 x + 4 \mathmr{and} {\left(x - \frac{3}{2}\right)}^{2} + 4 - \frac{9}{4} \mathmr{and} {\left(x - \frac{3}{2}\right)}^{2} + \frac{7}{4} \therefore$Vertex is at $\left(\frac{3}{2} , \frac{7}{4}\right)$ and axis of symmetry is $x = \frac{3}{2}$ graph{x^2-3x+4 [-10, 10, -5, 5]}[Ans]