Question

What is the axis of symmetry and vertex for the graph `y=x^2-4x+12`?

Answer 1

axis of symmetry: `x = 2`
vertex: `(2, 8)`

Explanation:

The equation must be in general form `f(x) = Ax^2 + Bx + C`

The axis of symmetry is `x = -B/(2A) = 4/2`

Therefore, the axis of symmetry: `x = 2`

`f(-B/(2A)) = f(2) = 2^2 -4(2) + 12 = 8`

vertex: `(2, 8)`