# What is the axis of symmetry and vertex for the graph y= x ^2 -8x?

Vertex is at $\left(4 , - 16\right)$ Axis of symmetry is $x = 4$
$y = {x}^{2} - 8 x = {\left(x - 4\right)}^{2} - 16 \therefore$Vertex is at $\left(4 , - 16\right)$ Axis of symmetry is $x = 4$ graph{x^2-8x [-40, 40, -20, 20]}[Ans]