Question

What is the axis of symmetry and vertex for the graph `y = x^2 -8x +10`?

Answer 1

Vertex is at `(4,-6)` and the axis of symmetry is `x=4`

Explanation:

`y=x^2-8x+10 or y= (x-4)^2 -16+10` or

`y=(x-4)^2 -6`. Comparing with vertex form of equation

`y=a(x-h)^2+k ; (h,k)` being vertex, we find here

`h=4 , k= -6`. Vertex is at `(4,-6)` and the axis of symmetry is

`x=4`
graph{x^2-8x+10 [-20, 20, -10, 10]} [Ans]