# What is the Cartesian form of (-1,(14pi)/3))?

Oct 1, 2016

$\left(x , y\right) = \left(\frac{1}{2} , - \frac{\sqrt{3}}{2}\right)$

#### Explanation:

$x = r \cos \left(\theta\right)$

$= \left(- 1\right) \cos \left(\frac{14 \pi}{3}\right)$

$= - \cos \left(\frac{2 \pi}{3}\right)$

$= - \left(- \frac{1}{2}\right)$

$= \frac{1}{2}$

$y = r \sin \left(\theta\right)$

$= \left(- 1\right) \sin \left(\frac{14 \pi}{3}\right)$

$= - \sin \left(\frac{2 \pi}{3}\right)$

$= - \frac{\sqrt{3}}{2}$