# What is the Cartesian form of ( 2 , ( - 15pi)/2 ) ?

Jan 8, 2018

$\left(0 , 2\right)$

#### Explanation:

For polar coordinates we have: $\left(r , \theta\right)$

For Cartesian coordinates we have $\left(x , y\right)$

$x = r \cos \left(\theta\right)$

$y = r \sin \left(\theta\right)$

$x = 2 \cos \left(\frac{- 15 \pi}{2}\right) = 0$

$y = 2 \sin \left(\frac{- 15 \pi}{2}\right) = 2$

$\therefore$

Cartesian coordinates:

$\left(0 , 2\right)$