Question

What is the Cartesian form of `(-25,(-3pi)/4))`?

Answer 1

The cartesian form is `( (25sqrt(2))/2, (25sqrt(2))/2 )`.

Explanation:

We can use `x=rcos(theta)` and `y=rsin(theta)` to convert:

`x=-25cos(-(3pi)/4)=-25(-sqrt(2)/2)=(25sqrt(2))/2`
`y=-25sin(-(3pi)/4)=-25(-sqrt(2)/2)=(25sqrt(2))/2`

So the cartesian form is `( (25sqrt(2))/2, (25sqrt(2))/2 )`.