What is the Cartesian form of #( -5 , ( - 16pi)/3 ) #? Calculus Polar Curves Introduction to Polar Coordinates 1 Answer Leland Adriano Alejandro Jan 12, 2016 #(5/2, (-5 sqrt(3))/2)# Explanation: #x=r cos theta# #x=-5*cos (-16 pi/3)# #x = 5/2# and #y=r*sin theta# #y=-5*sin (-16 pi/3)# #y=(-5sqrt(3))/2# Answer link Related questions How do you find the polar coordinates of #(-4,0)# ? How do you find the polar coordinates of the point #(-2,0)# ? Find the polar coordinates of the point with rectangular coordinates #(0,1)# ? How do you find the polar coordinates of the point with rectangular coordinates #(-2,2# )? How do polar coordinates work? How do you change polar coordinates to rectangular coordinates? What are polar coordinates used for in real life? How do you change rectangular coordinates to polar coordinates? How do you find the rectangular coordinates of the point with polar coordinates #(2,pi/4)#? How do you find the rectangular coordinates of the point with polar coordinates #(-1,pi/3)#? See all questions in Introduction to Polar Coordinates Impact of this question 1041 views around the world You can reuse this answer Creative Commons License