What is the center and radius of the circle with equation (x+8)^2+(y+3)^2=6.25?

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what is the center and radius of the circle with equation (x+8)^2+(y+3)^2=6.25

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Answer 1 · 2018-06-18T13:33:50

Refer to the explanation.

#(x-h)^2+(y-k)^2=r^2#

where:

#(h,k)# are the coordinates of the circle's center

#r# is the radius of the circle

Here, we see that #h=-8,k=-3#, and so the center of the circle is located at #(-8,-3)#.

The radius is therefore:

#r^2=6.25#

#:.r=sqrt(6.25)#

#=2.5 \ "units"#

graph{(x-8)^2+(y+3)^2=6.25 [-4.5, 15.5, -7.6, 2.4]}