What is the complex conjugate of #-2-sqrt5i#?

2 Answers
Sep 1, 2016

Answer:

#-2+sqrt5i#.

Explanation:

The complex conjugate of #x+iy# is #x-iy#.

Hence, the complex conjugate of #-2-isqrt5# is

#-2+sqrt5i#.

Sep 1, 2016

Answer:

#-2+sqrt5i#

Explanation:

Given a complex number #z=a+-bi#

Then the complex conjugate #barz# is

#color(red)(|bar(ul(color(white)(a/a)color(black)(barz=a∓bi)color(white)(a/a)|)))#

Note that the real part , remains unchanged while the #color(red)"sign"# of the imaginary part reverses.

Thus the conjugate is #-2+sqrt5i#