What is the concentration (M) of an aqueous methanol produced when 0.200 L of a 2.00 M solution was diluted to 0.800 L?

1 Answer
Nov 3, 2015

Answer:

#M=0.5 M#

Explanation:

#M=(mol)/L#

Calculating moles before dilution:

#mol=M*L=2.0M*0.2L=0.4 mol#

The amount of moles stays the same, although we increase the volume. But we se from the formula #mol=M*L# that the molarity will change.

we know amount of moles, and liters:

#M=(0.4mol)/(0.8L)=0.5 M#