# What is the concentration (M) of an aqueous methanol produced when 0.200 L of a 2.00 M solution was diluted to 0.800 L?

Nov 3, 2015

$M = 0.5 M$

#### Explanation:

$M = \frac{m o l}{L}$

Calculating moles before dilution:

$m o l = M \cdot L = 2.0 M \cdot 0.2 L = 0.4 m o l$

The amount of moles stays the same, although we increase the volume. But we se from the formula $m o l = M \cdot L$ that the molarity will change.

we know amount of moles, and liters:

$M = \frac{0.4 m o l}{0.8 L} = 0.5 M$