# What is the concentration of a 450 mL solution that contains 200 grams of iron (II) chloride?

$\text{Concentration}$ $=$ $\text{Moles of solute"/"Litres of solution}$
$\text{Moles of solute}$ $=$ $\frac{200 \cdot g}{126.75 \cdot g \cdot m o {l}^{-} 1}$ $=$ $1.58 \cdot m o l$
$\text{Concentration}$ $=$ $\frac{1.58 \cdot m o l}{450 \times {10}^{-} 3 \cdot L}$ $=$ $3.5 \cdot m o l \cdot {L}^{-} 1$ with respect to $F e C {l}_{2}$.