What is the concentration of a solution with a volume of 660 mL that contains 33.4 grams of aluminum acetate (molar mass 204.1)?

1 Answer
May 6, 2018

Recall,

#"M" = "mol"/"L"#

Aluminum acetate is merely three acetate anions coordinated about an aluminum counterion.

Hence, the solution is,

#(33.4"g" * (Al(CH_3COO)_3)/(204.1"g"))/(0.660"L") approx 0.248"M"#

in concentration, given your data.