What is the concentration of ammonia if 15.34 mL of 1.14 M HCl is needed to titrate a 10.00 mL sample of the cleaner?

1 Answer
Apr 19, 2018

We address the reaction: #HCl(aq) + NH_3(aq) rarr NH_4^(+)Cl^(-)(aq)#

Explanation:

And there are thus 1:1 equivalence between ammonium ion (whose concentration we assessed), and ammonia....

And so....#[NH_3]="Moles of ammonia"/"Volume of solution"#

#=(15.34xx10^-3Lxx1.14*mol*L^-1)/(10.00xx10^-3*L)=1.75*mol*L^-1#