# What is the concentration of nitrate ions in a 3.79M Mg(NO_3)_2 solution?

If the solution has a concentration of $3.79$ $m o l$ ${L}^{-} 1$ in $M g {\left(N {O}_{3}\right)}_{2}$, then the concentration of the nitrate is twice this value.
$M g {\left(N {O}_{3}\right)}_{2} \left(s\right) \rightarrow M {g}^{2 +} + 2 N {O}_{3}^{-}$
[Mg^(2+)] = 3.79 mol*L^-1; [NO_3^-] = ??