# What is the correct option of the following question?

##### 1 Answer

#### Answer

#### Answer:

#### Explanation

#### Explanation:

#### Answer:

The answer is

#### Explanation:

**For this problem I assume that #log(a) = ln(a)#**

Let's rewrite the denominator in terms of sine and cosine exclusively.

#secx - cosx= 1/cosx - cosx = (1 -cos^2x)/cosx = sin^2x/cosx#

We can also use the laws of logarithms to simplify the numerator to

#ln[(1 + x + x^2)(1 - x + x^2)]#

Now let's rewrite the limit.

#L = lim_(x-> 0) (ln[(1 +x +x^2)(1 -x + x^2)])/(sin^2x/cosx)#

#L = lim_(x->0) (cosxln[(1 +x + x^2)(1 - x+ x^2)])/sin^2x#

If we try to evaluate the limit now, we will get

Finding the derivative of the numerator may be a little bit long. We must first differeintaite

Start by expanding within the brackets:

#1 - x + x^2 + x - x^2 + x^3 + x^2 - x^3 + x^4#

Now combine like terms

#x^4 + x^2 + 1#

Now differentiate using the chain and power rules.

#d/dx(ln(x^4 + x^2 + 1)) = (4x^3 + 2x)/(x^4 + x^2 + 1)#

Now use the product rule to differentiate the entire numerator.

#L = lim_(x->0) (-sinxln(x^4 +x^2 + 1) + cosx((4x^3 + 2x)/(x^4 + x^2 + 1)))/(sin(2x))#

You will find that this gives

It's tedious, but in the end you should get an answer of

Hopefully this helps!

Describe your changes (optional) 200