Question

What is the critical number of h(t)=6t²-t-2?

Answer 1

there is one critical value, which occurs when `t=1/12`.

Explanation:

We have:

`h(t) = 6t^2-t-2`

We obtain the critical numbers by finding the values of `t` which make the first derivative vanish, so we differentiate wrt `t` to obtain the first derivative:

`h'(t) = 12t-1`

And for the first derivative to vanish we require that:

`h'(t) = 0 => 12t-1 = 0`
`:. t =1/12`

Hence there is one critical value, which occurs when `t=1/12`.