What is the definite integral?

Question

#int_3^4 (2 +u^2)/u^3 du#

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Answer 1 · 2017-12-05T17:54:02

#int_3^4 (2+u^2)/u^3*du=7/144+ln(4/3)#

#int_3^4 (2+u^2)/u^3*du#

=#int_3^4 2u^(-3)*du#+#int_3^4 (du)/u#

=#[-u^(-2)]_3^4#+#[Lnu]_3^4#

=#-1/16-(-1/9)+ln4-ln3#

=#7/144+ln(4/3)#