# What is the density of a mineral with a mass of 12.4 g and a volume of 1.2 cm^3?

Aug 28, 2016

The density is 1$0.3 {\text{ grams/cm}}^{3}$

#### Explanation:

Density = $\frac{M}{V}$

the mass is $12.4 g$

The volume is $1.2 c {m}^{3} = 1.2 m l$

$1 m l = 1 c {m}^{3}$

So $\frac{12. 4 g}{1.2 c {m}^{3}} = 10.3 {\text{g/cm}}^{3}$

To the correct number of significant digits the answer is
$10 {\text{g/cm}}^{3}$

This would be the approximate density of iron ore.