Question

What is the density of a mineral with a mass of 12.4 g and a volume of 1.2 cm^3?

Answer 1

The density is 1`0.3" grams/cm"^3`

Explanation:

Density = `M/V`

the mass is `12.4g`

The volume is `1.2 cm^3 = 1.2 ml`

`1 ml = 1 cm^3`

So `(12. 4 g)/ (1.2 cm^3) = 10.3 "g/cm"^3`

To the correct number of significant digits the answer is
`10 "g/cm"^3`

This would be the approximate density of iron ore.