What is the density of a mineral with a mass of 12.4 g and a volume of 1.2 cm^3?

1 Answer

Answer:

The density is 1#0.3" grams/cm"^3#

Explanation:

Density = #M/V#

the mass is #12.4g#

The volume is #1.2 cm^3 = 1.2 ml #

# 1 ml = 1 cm^3#

So # (12. 4 g)/ (1.2 cm^3) = 10.3 "g/cm"^3#

To the correct number of significant digits the answer is
#10 "g/cm"^3 #

This would be the approximate density of iron ore.