What is the density of a mineral with a mass of #412# #g# and a volume of #8.2# #cm^3#?

1 Answer
Jun 14, 2016

Answer:

#50.2g/(cm^(3))#

Explanation:

In order to determine the density of the mineral, we have to use the following formula:

#D=M/V#

  • D represents density and it will have units of #g/(mL)# when talking about a liquid or units of #g/(cm^3)# when talking about a solid.
  • M represents mass and will have units of grams #g#.
  • V represents volume and it will have units of #mL# or #cm^(3)#

We know the mass and volume, both of which have the appropriate units so all we have to do is plug the numbers into the formula:

#D = (412g)/(8.2cm^(3))#

#D = 50.2g/(cm^(3))#