Question

What is the density of a mineral with a mass of `412` `g` and a volume of `8.2` `cm^3`?

Answer 1

`50.2g/(cm^(3))`

Explanation:

In order to determine the density of the mineral, we have to use the following formula:

`D=M/V`

• D represents density and it will have units of `g/(mL)` when talking about a liquid or units of `g/(cm^3)` when talking about a solid.
• M represents mass and will have units of grams `g`.
• V represents volume and it will have units of `mL` or `cm^(3)`

We know the mass and volume, both of which have the appropriate units so all we have to do is plug the numbers into the formula:

`D = (412g)/(8.2cm^(3))`

`D = 50.2g/(cm^(3))`