What is the density of a piece of wood with a mass of 343 g and a volume of 45 cm^3?

Feb 5, 2016

$D \approx 7.6 \frac{g}{c {m}^{3}}$

Explanation:

The density of an object is its mass per unit volume. In this case, it can be computed using the formula below:

$\rho = \frac{m}{v}$
Where $\rho$ is the density, $m$ is the mass of the object while $v$ is the volume.

Since in this question you are given both the mass and the volume, you just need to plug in the values...

[Given]
$m = 343 g$
$v = 45 c {m}^{3}$

[Solution]
$D = \frac{343 g}{45 c {m}^{3}}$
$D \approx 7.622 \frac{g}{c {m}^{3}}$
$D \approx 7.6 \frac{g}{c {m}^{3}}$

Note that the density of an object or substance can be expressed in different units. Some of the more commonly used are:
- $\frac{g}{c {m}^{3}}$ or $\frac{g}{m L}$
- $k \frac{g}{m} ^ 3$