What is the derivative of #(1 - x)^0.5#? Calculus Basic Differentiation Rules Chain Rule 1 Answer maganbhai P. Jul 23, 2018 #y=(1-x)^(0.5)=(1-x)^(1/2)=sqrt(1-x)# #=>(dy)/(dx)=-1/(2sqrt(1-x))# Explanation: Let , #y=(1-x)^(0.5)# #:.y=(1-x)^(1/2)# #=>(dy)/(dx)=1/2(1-x)^(1/2-1)d/(dx)(1-x)# #=>(dy)/(dx)=1/2(1-x)^(-1/2) (-1)# #=>(dy)/(dx)=-1/(2(1-x)^(1/2))=-1/(2sqrt(1-x))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 7346 views around the world You can reuse this answer Creative Commons License