What is the derivative of #e^3#?

2 Answers
Dec 10, 2014

Since #e^3# is a constant, its derivative is zero.

#(e^3)'=0#


I hope that this was helpful.

The derivative of #e^3# is #0#.

The base of natural logarithms #e#, also called Euler's constant, is an irrational number, with an approximation of it's value correct to 7 decimal places being #2.7182818#.

#e^3# is, therefore, a numeber too (it can be show to be irrational). And since the derivative of a constant function is always #0#, it's derivative is #0#.