# What is the derivative of e^3?

Dec 10, 2014

Since ${e}^{3}$ is a constant, its derivative is zero.

$\left({e}^{3}\right) ' = 0$

I hope that this was helpful.

The derivative of ${e}^{3}$ is $0$.

The base of natural logarithms $e$, also called Euler's constant, is an irrational number, with an approximation of it's value correct to 7 decimal places being $2.7182818$.

${e}^{3}$ is, therefore, a numeber too (it can be show to be irrational). And since the derivative of a constant function is always $0$, it's derivative is $0$.