# What is the derivative of ln(2x^2+1)?

$y ' = \frac{4 x}{2 {x}^{2} + 1}$
$y ' = \frac{1}{2 {x}^{2} + 1} \cdot \left(2 {x}^{2} + 1\right) ' = \frac{1}{2 {x}^{2} + 1} \cdot 4 x = \frac{4 x}{2 {x}^{2} + 1}$