What is the derivative of #ln sqrt(2x+1)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Jim H Nov 1, 2017 #lnsqrt(2x+1) = ln((2x+1)^1/2) = 1/2 ln(2x+1)# Explanation: So, the derivative is #1/2[1/(2x+1) * d/dx(2x+1) = 1/2 [1/(2x+1) * 2] = 1/(2x+1)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 4911 views around the world You can reuse this answer Creative Commons License