Question

What is the derivative of `pi^sinx`?

Answer 1

Letting `y=pi^(sin(x))`, we get

`y' = pi^(sin(x)) * cos(x) * ln(pi)` by the chain rule.

Explanation:

The derivatives of exponential functions with base `a` states that

`d/dx[a^(x)] = a^(x) * ln(a)`.