What is the derivative of #sin^2 x + cos^2 x#? Calculus Basic Differentiation Rules Chain Rule 1 Answer P dilip_k Jul 8, 2016 0 Explanation: Here #y = sin^2x + cos^2x=1# #:. (dy)/(dx)=d/(dx)(1)=0# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 858 views around the world You can reuse this answer Creative Commons License