# What is the derivative of sin(3 - (pi)x)?

$\frac{d}{\mathrm{dx}} \left(\sin \left(3 - \pi x\right)\right) = - \pi \cdot \cos \left(3 - \pi x\right)$

#### Explanation:

$\frac{d}{\mathrm{dx}} \left(\sin \left(3 - \pi x\right)\right) = \cos \left(3 - \pi x\right) \frac{d}{\mathrm{dx}} \left(3 - \pi x\right)$

take note that $3$ and $\pi$ are constants

$\frac{d}{\mathrm{dx}} \left(\sin \left(3 - \pi x\right)\right) = \cos \left(3 - \pi x\right) \cdot \left(0 - \pi\right)$

$\frac{d}{\mathrm{dx}} \left(\sin \left(3 - \pi x\right)\right) = - \pi \cdot \cos \left(3 - \pi x\right)$

God bless....I hope the explanation is useful.