What is the derivative of #sin^5(x)#?
1 Answer
Aug 23, 2016
Explanation:
differentiate using the
#color(blue)"chain rule "#
#color(red)(|bar(ul(color(white)(a/a)color(black)(dy/dx=(dy)/(du)xx(du)/(dx))color(white)(a/a)|)))........ (A)# let
#y=sin^5x=(sinx)^5# let
#u=sinxrArr(du)/(dx)=cosx# and
#y=u^5rArr(dy)/(du)=5u^4# substitute these values into (A) convert u back to x
#rArrdy/dx=5u^4(cosx)=5sin^4xcosx#