Question

What is the derivative of `sqrt(7x)`?

Answer 1

`7/(2sqrt(7x))`

Explanation:

rewrite the function as: `sqrt(7x) = (7x )^(1/2 )`

applying the 'chain rule' : `1/2 (7x)^(-1/2 ). d/dx (7x)`

= `1/2 (7x)^(-1/2)(7) = 7/(2sqrt(7x))`

Answer 2

`sqrt7/(2sqrtx)`, or, if you disapprove of radicals in the denominator, it is `sqrt(7x)/(2x)`

Explanation:

`sqrt(7x) = sqrt7sqrtx` and `d/dx(sqrtx)=1/(2sqrtx)`.

Therefore,

`d/dx(sqrt(7x)) = sqrt7d/dx(sqrtx) = sqrt7(1/(2sqrtx)) = sqrt7/(2sqrtx)`.

Eliminate the square root from the denominator if necessary.