What is the derivative of #sqrt(8x+1)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer sente Mar 28, 2016 #d/dxsqrt(8x+1) =4/sqrt(8x+1)# Explanation: Applying the chain rule: #d/dxsqrt(8x+1) = d/dx(8x+1)^(1/2)# #= 1/2(8x+1)^(-1/2)*(d/dx(8x+1))# #=1/(2sqrt(8x+1))*8# #=4/sqrt(8x+1)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 4073 views around the world You can reuse this answer Creative Commons License