# What is the derivative of this function arcsin(x^2)?

Jun 1, 2018

$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{2 x}{\sqrt{1 - {x}^{4}}}$

#### Explanation:

$y = {\sin}^{-} 1 \left({x}^{2}\right)$

Using Chain Rule,

$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{1}{\sqrt{1 - {x}^{4}}} \times 2 x$

$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{2 x}{\sqrt{1 - {x}^{4}}}$