What is the derivative of #y= ln(1 + e^(2x))#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Konstantinos Michailidis Dec 26, 2015 The derivative is #d(ln(1+e^(2x)))/dx=((1+e^(2x))')/(1+e^(2x))=2*e^(2x)/(1+e^(2x)# Finally #dy/dx=(2*e^(2x))/(1+e^(2x))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 2663 views around the world You can reuse this answer Creative Commons License